# How do you find value of discriminant then describe number and type of solutions for x^2 - 16x + 64 = 0?

Jan 4, 2017

Solution of a general quadratic equation of the form $a {x}^{2} + b x + c = 0$ is $x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$ .
In the present case, comparing the coefficients with the general equation, a=1, b= -16 and c=64. Thus the Discriminant would be ${\left(- 16\right)}^{2} - 4 \left(1\right) \left(64\right)$ = 0. Hence the solution would be both the roots being equal to 8