# How do you find vertical and horizontal asymptotes of #(4x)/(x-3)#?

##### 1 Answer

Aug 19, 2015

There is a vertical asymptote at

#### Explanation:

**Step 1.** Find the vertical asymptotes.

Set the denominator equal to zero and solve for

There is a vertical asymptote at

**Step 3.** Find the horizontal asymptotes.

Since the numerator and denominator are the same degree, we must divide the coefficients of the highest terms.

The horizontal asymptote is at