How do you find vertical, horizontal and oblique asymptotes for (3x^2 + 4)/(x+1)3x2+4x+1?
1 Answer
The vertical asymptote is
The oblique asymptote is
Explanation:
As you canot divide by
As the degree of the numerator is
Therefore we do a lond division
So,
So the oblique asymptote is
So there is no horizontal asymptote
graph{(y-(3x^2)/(x+1))(y-3x+3)=0 [-43.83, 38.34, -24.63, 16.5]}