How do you find vertical, horizontal and oblique asymptotes for #f(x) = (3x+5)/(x-6)#?
vertical asymptote at x = 6
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
#x-6=0rArrx=6" is the asymptote"#