# How do you find vertical, horizontal and oblique asymptotes for # f(x)= (x^2-4x+4) /( x+1)#?

##### 1 Answer

May 27, 2017

#### Answer:

**Vertical asymptote at** **horizontal asymptote is absent.**

**is the oblique asymptote.**

#### Explanation:

Vertical asymptote: Solving denominator for zero we get

Since degree of numerator(2) is greater than denominator(1) horizontal asymptote is absent.

Since degree of numerator(2) is greater than denominator(1) by a margin of 1 there is a slant/oblique asymptote , which can be found by long division.

So straight line

graph{(x^2-4x+4)/(x+1) [-80, 80, -40, 40]} [Ans]