# How do you find vertical, horizontal and oblique asymptotes for #f(x)= (x^3+8) /(x^2+9)#?

##### 1 Answer

Dec 4, 2016

#### Answer:

The oblique asymptote is

No vertical and horizontal asymptotes

#### Explanation:

The domain of

The denominator

So there are no vertical asymptotes.

As the degree of the numerator is

Let's do a long division

So,

So, the oblique asymptote is

To calculate the limits as

graph{(y-(x^3+8)/(x^2+9))(y-x)=0 [-5.546, 5.55, -2.773, 2.774]}