# How do you find vertical, horizontal and oblique asymptotes for h(x)=5^(x-2)?

$y = 0$
The function $f \left(x\right) = {5}^{x}$ has horizontal asymptote $y = 0$ because as $x \to - \infty$, $f \left(x\right) \to 0$ and no other asymptotes.
$h \left(x\right) = {5}^{x} - 2$ is a horizontal shift of $f \left(x\right)$ by 2 units to the right, so the range is not impacted. That means the horizontal asymptote is still $y = 0$. The function has no other asymptotes.