How do you find vertical, horizontal and oblique asymptotes for #h(x)=5^(x-2)#?

1 Answer
turksvids
Jan 25, 2018

#y=0#

Explanation:

The function #f(x)=5^x# has horizontal asymptote #y=0# because as #x to -oo#, #f(x) to 0# and no other asymptotes.

#h(x)=5^x-2# is a horizontal shift of #f(x)# by 2 units to the right, so the range is not impacted. That means the horizontal asymptote is still #y=0#. The function has no other asymptotes.

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