# How do you find vertical, horizontal and oblique asymptotes for #(x^2-2x)/(x+1)#?

##### 1 Answer

The vertical asymptote is

The oblique asymptote is

No horizontal asymptote

#### Explanation:

Let

The domain of

As you cannot divide by

So, the vertical asymptote is

The degree of the numerator is

Let's do a long division

So,

Therefore

The oblique asymptote is

To calculate the limits as

graph{(y-(x^2-x)/(x+1))(y-x)=0 [-36.53, 36.57, -18.26, 18.27]}