# How do you find vertical, horizontal and oblique asymptotes for #(x^3-8)/(x^2-5x+6)#?

##### 1 Answer

Jun 13, 2018

#### Answer:

the oblique asymptote is

#### Explanation:

=

Therefore, the oblique asymptote is

The horizontal asymptote is found by letting the denominator equal to 0.

The oblique asymptote is found by long division