# How do you find vertical, horizontal and oblique asymptotes for #(x^3-8)/(x^2 –5x+6)#?

##### 1 Answer

Mar 20, 2016

Vertical Asymptote:

Oblique Asymptote:

Horizontal Asymptote: None

#### Explanation:

To obtain the oblique asymptote, we divide by long division

the linear part (x+5) of the quotient will used for the oblique asymptote, that is

The following includes the oblique asymptote

graph{(y-(x^3-8)/(x^2-5x+6))(y-x-5)=0[-80,80,-40,40]}

God bless....I hope the explanation is useful.