# How do you find vertical, horizontal and oblique asymptotes for #y=(x^3-x^2-10)/(3x^2-4x)#?

##### 1 Answer

May 22, 2017

#### Answer:

**Vertical asymtotes are** **No H.A**.

**Oblique asymptote is**

#### Explanation:

Vertical asymtotes are

Since degree of numerator is greater than degree of numerator there is no horizontal asymtote.

By long division we can find oblique asymptote as

graph{(x^3-x^2-10)/(3x^2-4x) [-40, 40, -20, 20]} [Ans]