How do you find w(-1) given w(x)=x^3-2?

1 Answer
Oct 1, 2016

$w \left(- 1\right) = - 3$

Explanation:

$w \left(x\right) = {x}^{3} - 2$ means $w$ is a function of $x$. To find the value of $w \left(x\right)$ at any given value of $x$, we just substitute $x$ in the function. Hence

$w \left(- 1\right) = {\left(- 1\right)}^{3} - 2$

= $- 1 - 2$

= $- 3$