How do you find x and y intercepts of # -5x + 6y = 30#?

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Answer 1 · 2017-04-08T02:25:43

See the entire solution process below:

To find the y-intercept, set #x = 0# and solve for #y#:

#-5x + 6y = 30# becomes:

#(-5 xx 0) + 6y = 30#

#0 + 6y = 30#

#6y = 30#

#(6y)/color(red)(6) = 30/color(red)(6)#

#(color(red)(cancel(color(black)(6)))y)/cancel(color(red)(6)) = 5#

#y = 5#

The y-intercept is #y = 5# or #(0, 5)#

To find the x-intercept, set #y = 0# and solve for #x#:

#-5x + 6y = 30# becomes:

#-5x + (6 xx 0) = 30#

#-5x + 0 = 30#

#-5x = 30#

#(-5x)/color(red)(-5) = 30/color(red)(-5)#

#(color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5)) = -6#

#x = -6#

The x-intercept is #x = -6# or #(-6, 0)#