Question

How do you give the six trigonometric function values of 19pi/3?

Answer 1

Find 6 trig functions

Explanation:

Trig table and unit circle give -->
`sin ((19pi)/3) = sin (pi/3 + (18pi)/3) = sin (pi/3 + 6pi) =`
`= sin (pi/3) = sqrt3/2`
`cos ((19pi)/3) = cos (pi/3) = 1/2`
`tan ((19pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3`
`cot ((19pi)/3) = 1/sqrt3 = sqrt3/3`
`sec ((19pi)/3) = 1/(cos) = 2`
`csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3`