How do you give the six trigonometric function values of -3pi?

1 Answer
Mar 19, 2017

#sin(-3pi) = 0, cos(-3pi) = -1, tan(-3pi) = 0#
#csc(-3pi) = "undefined", sec(-3pi) = -1#,
#cot(-3pi) = "undefined"#

Explanation:

#-3pi# has the same values as #pi# due to the periodic nature of trigonometric functions. The negative sign means start at the #x-#axis and go clockwise #3 * 180^@# since #pi = 180^@#

#sin pi = sin(-3pi) = 0#

#cos pi = cos(-3pi) = -1#

#tan pi = (sin pi)/(cos pi) = 0/-1 = 0#

#csc pi = 1/(sin pi) = 1/0 = "undefined"#

#sec pi = 1/(cos pi) = 1/-1 = -1#

#cot pi = 1/(cot pi) = 1/0 = "undefined"#