How do you graph #-10x+15y=60# using intercepts?

1 Answer
Aug 19, 2017

Answer:

See a solution process below:

Explanation:

x-intercept

To find the #x#-intercept we set #y# to #0# and solve for #x#:

#-10x + (15 * 0) = 60#

#-10x + 0 = 60#

#-10x = 60#

#(-10x)/color(red)(-10) = 60/color(red)(-10)#

#(color(red)(cancel(color(black)(-10)))x)/cancel(color(red)(-10)) = -6#

#x = -6# or #(-6, 0)#

y-intercept

To find the #y#-intercept we set #x# to #0# and solve for #y#:

#(-10 xx 0) + 15y = 60#

#0 + 15y = 60#

#15y = 60#

#(15y)/color(red)(15) = 60/color(red)(15)#

#(color(red)(cancel(color(black)(15)))y)/cancel(color(red)(15)) = 4#

#y = 4# or #(0, 4)#

We can now plot the two points and draw a line through them to graph the equation:

graph{((x+6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)(-10x+15y-60)=0}