How do you graph 2(x-3)^2+2y^2=8?

Reduce to the standard form ${\left(x - 3\right)}^{2} + {y}^{2} = {2}^{2}$.
The equation ${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$ represents the locus of the point that moves at a constant distance r from (a, b)..