Question

How do you graph `2(x-3)^2+2y^2=8`?

Answer 1

Reduce to the standard form `(x-3)^2+ y^2 = 2^2`.
This represents the circle with center at (3. 0) and radius = 2.

Explanation:

The equation `(x-a)^2+(y-b)^2 = r^2` represents the locus of the point that moves at a constant distance r from (a, b)..