# How do you graph 2x-1=y using the intercepts?

Nov 2, 2017

See a solution process below:

#### Explanation:

First, solve for the $x$ and $y$-intercepts and plot these points:

x-intercept - set y = 0 and solve for x:

$2 x - 1 = 0$

$2 x - 1 + \textcolor{red}{1} = 0 + \textcolor{red}{1}$

$2 x - 0 = 1$

$2 x = 1$

$\frac{2 x}{\textcolor{red}{2}} = \frac{1}{\textcolor{red}{2}}$

$x = \frac{1}{2}$ or $\left(\frac{1}{2} , 0\right)$

y-intercept - set x = 0 and solve for y:

$\left(2 \times 0\right) - 1 = y$

$0 - 1 = y$

$- 1 = y$

$y = - 1$ or $\left(0 , - 1\right)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-(1/2))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x-1-y)(x^2+(y+1)^2-0.025)((x-(1/2))^2+y^2-0.025)=0 [-10, 10, -5, 5]}