How do you graph #2x + 3y =-6# by plotting points?

1 Answer
Jun 15, 2018

#"see explanation"#

Explanation:

#"one way is to find the intercepts, that is where the graph"#
#"crosses the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = o, in the equation for x-intercept"#

#x=0rArr0+3y=-6rArry=-2larrcolor(red)"y-intercept"#

#y=0rArr2x+0=-6rArrx=-3larrcolor(red)"x-intercept"#

#"plot the points "(0,-2)" and "(-3,0)#

#"draw a straight line through them for graph"#
graph{(y+2/3x+2)((x-0)^2+(y+2)^2-0.04)((x+3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}