# How do you graph -2x+7y=-7 by plotting points?

Jun 17, 2018

Here is the graph with two key points indicated by small circles:
graph{(x^2+(y+1)^2-0.005)((x-(7/2))^2+y^2-0.005)(7-2x+7y)=0 [-0.376, 5.1, -1.764, 0.97]}

#### Explanation:

Since the given equation: $- 2 x + 7 y = - 7$ is linear,
we only need 2 points to establish the required line.

The simplest points to evaluate are
[1]$\textcolor{w h i t e}{\text{XXX}}$when $x = 0 \rightarrow \left(x , y\right) = \left(0 , - 1\right)$
[2]$\textcolor{w h i t e}{\text{XXX}}$when $y = 0 \rightarrow \left(x , y\right) = \left(\frac{7}{2} , 0\right)$

If we plot these points on the Cartesian plane and draw a straight line through them we will get the required graph.