Question

How do you graph `2y < 8x - 4` on a coordinate graph?

Answer 1

Graph linear inequality: 2y < 8x - 4

Explanation:

First, bring the inequality to standard form:
2y - 8x + 4 < 0. (1)
Next, graph the Line -> 2y - 8x + 4 = 0 by its 2 intercepts.
To find y-intercept, make x = 0 --> y = - 2.
To find x-intercept, make y = 0 --> x = 4/8 = 1/2.
To find the solution set of the inequality (1), use the origin as test point. Replace x = 0 and y = 0 into the inequality (1). We get: 4 < 0. Not true! Then, the solution set area doesn't contain O. The area below the line is the answer. Color it.
graph{2y - 8x + 4 = 0 [-10, 10, -5, 5]}