Question

How do you graph `-2y=-x+8` by plotting points?

Answer 1

`"see explanation"`

Explanation:

`"one way is to find the intercepts, that is where the"`
`"graph crosses the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr-2y=8rArry=-4larrcolor(red)"y-intercept"`

`y=0rArr-x+8=0rArrx=8larrcolor(red)"x-intercept"`

`"plot the points "(0,-4)" and "(8,0)`

`"draw a straight line through them for graph"`
graph{(y-1/2x+4)((x-0)^2+(y+4)^2-0.04)((x-8)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}