How do you graph #3x+2y=2# by plotting points?

1 Answer
Feb 29, 2016

Refer to the Explanation.

Explanation:

First convert the standard equation for a line to the slope-intercept form by solving for #y#. Slope-intercept form is #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

#3x+2y=2#

Subtract #3x# from both sides.

#2y=-2-3x#

Divide both sides by #2#.

#y=-2/2-3/2x#

Simplify.

#y=1-2/3x#

Rearrange into slope-intercept form.

#y=-2/3x+1#

Now find two points on the line by choosing values for #x# and solving for #y#.

#x=0,# #y=1#
#x=3,# #y=-1#

Plot the points on a graph and draw a straight line through the two points.

graph{y=-2/3x+1 [-10, 10, -5, 5]}