# How do you graph 3x-5y= 10 using the slope and y intercept?

##### 1 Answer
Feb 5, 2015

You first work this into a standard form $y = a x + b$

Step 1: $x$'s to the right:
$3 x - 5 y = 10 \to - 5 y = - 3 x + 10$

Step 2: divide everything by $- 5$ to get the $y$
$\frac{- 5 y}{- 5} = \frac{- 3 x}{- 5} + \frac{10}{- 5} \to y = \frac{3}{5} x - 2$

Now your slope is $\frac{3}{5}$ and your $y$-intercept is $- 2$

Graphing:
One point is $\left(0 , - 2\right)$, the $y$-intercept
Take any $x$-value and plug it in the equation, let's say $5$
this gives you $y = \frac{3}{5} \cdot 5 - 2 = 1$, so $\left(5 , 1\right)$
Draw the line:
graph{0.6x-2 [-10, 10, -5, 5]}