# How do you graph y=-3x+5 using slope intercept form?

Nov 5, 2014

Let us sketch the graph of $y = - 3 x + 5$.

Step 1: Since the $y$-intercept is $5$, plot the point $\left(0 , 5\right)$, which looks like:

Step 2: Since the slope is $- 3$, move 1 unit to the right and 3 units down, so plot the point $\left(1 , 2\right)$, which looks like:

Step 3: Connect those points by a straight line, which looks like:

The line in green above is the graph of $y = - 3 x + 5$.

I hope that this was helpful.

Nov 5, 2014

The straight line equation written in slope intercept form is $y = m x + b$, in which $m$ is the slope, and $b$ is the $y$-intercept.

The equation $y = - 3 x + 5$ is in slope intercept form, and represents a straight line in which -3 is the slope, and 5 is the $y$-intercept. In order to determine ordered pairs that can be graphed, substitute any number for $x$ and solve for $y$.

If $x$ = 0, $y$ = 5: Ordered pair = (0, 5)
If $x$ = 1, $y$ = 2: Ordered pair = (1, 2)
If $x$ = 2, $y$ = -1: Ordered pair = (2, -1)
If $x$ = 3, $y$ = -3: Ordered pair = (3, -3)