Question

How do you graph `4x+2y=6` using intercepts?

Answer 1

`"see explanation"`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr0+2y=6rArry=3larrcolor(red)"y-intercept"`

`y=0rArr4x+0=6rArrx=3/2larrcolor(red)"x-intercept"`

`"Plot the points "(0,3)" and "(3/2,0)`

`"and draw a straight line through them for graph"`
graph{(y+2x-3)((x-0)^2+(y-3)^2-0.04)((x-3/2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}