How do you graph #4x+2y=6# using intercepts?

1 Answer
May 12, 2018

Answer:

#"see explanation"#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArr0+2y=6rArry=3larrcolor(red)"y-intercept"#

#y=0rArr4x+0=6rArrx=3/2larrcolor(red)"x-intercept"#

#"Plot the points "(0,3)" and "(3/2,0)#

#"and draw a straight line through them for graph"#
graph{(y+2x-3)((x-0)^2+(y-3)^2-0.04)((x-3/2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}