How do you graph 4x-3y=12 using intercepts?

Aug 18, 2017

$\text{see explanation}$

Explanation:

$\text{find the intercepts as follows}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$x = 0 \to 0 - 3 y = 12 \Rightarrow y = - 4 \leftarrow \textcolor{red}{\text{ y-intercept}}$

$y = 0 \to 4 x - 0 = 12 \Rightarrow x = 3 \leftarrow \textcolor{red}{\text{ x-intercept}}$

$\text{plot the points "(0,-4),(3,0)}$

$\text{and draw a straight line through them for graph}$
graph{4/3x-4 [-10, 10, -5, 5]}