How do you graph #4x-3y=12# using intercepts?

1 Answer
Aug 18, 2017

Answer:

#"see explanation"#

Explanation:

#"find the intercepts as follows"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0to0-3y=12rArry=-4larrcolor(red)" y-intercept"#

#y=0to4x-0=12rArrx=3larrcolor(red)" x-intercept"#

#"plot the points "(0,-4),(3,0)"#

#"and draw a straight line through them for graph"#
graph{4/3x-4 [-10, 10, -5, 5]}