How do you graph #4x+y=-1# using intercepts?

1 Answer
May 28, 2017

Answer:

Sub in the variables as #0# and solve for the other variable.

In this case, #x=-1/4# and #y=-1#.

Explanation:

All we have to do is sub in the variables as #0# and solve for the other variable.

#x#-intercept

Here, we are solving for the #x#-intercept. Thus, we have to sub #y=0#.

#4x+y=-1#

#4x+0=-1#

Now, let's bring like terms together and add them.

#4x=-1#

Now, we can isolate for #x#.

#(4x)/4=-1/4#

#x=-1/4#

Therefore, because #x=-1/4#, the #x#-intercept is #(-1/4,0)#.


#y#-intercept

Now, if we're solving for the #y#-intercept, we would have to sub in #x=0#.

#4x+y=-1#

#4(0)+y=-1#

Now, we add like terms,.

#y=-1#

Therefore, because #y=-1#, the #x#-intercept is #(0, -1)#.

We can double check our work by graphing the equation:

graph{4x+y=-1 [-10, 10, -5, 5]}

As you can see, the intercepts on the graph match with what we solved for!

Hope this helps :)