# How do you graph 4x+y=-8 using intercepts?

May 14, 2017

$y$-intercept at $\left(0 , - 8\right)$.

#### Explanation:

$y = - 4 x - 8$

The $y$-intercept of a straight line $y = m x + c$ is given by $c$.

Here $c = - 8$. so the graph intersects at $\left(0 , - 8\right)$ with a gradient $m$, in this case $- 4$.

graph{y = -4x-8 [-10, 10, -5, 5]}