How do you graph #5x+10y=30# using intercepts?
1 Answer
Apr 27, 2017
see explanation.
Explanation:
#"to find the x/y intercepts"#
#• " let x = 0, in the equation, for y-intercept"#
#• " let y = 0, in equation, for x-intercept"#
#x=0to0+10y=30toy=3larrcolor(red)" y-intercept"#
#y=0to5x+0=30tox=6larrcolor(red)" x-intercept"#
#"plot the points " (0,3)" and " (6,0)# draw a straight line through them and you have the graph.
graph{-1/2x+3 [-10, 10, -5, 5]}