How do you graph #5x+10y=30# using intercepts?

1 Answer
Apr 27, 2017

Answer:

see explanation.

Explanation:

#"to find the x/y intercepts"#

#• " let x = 0, in the equation, for y-intercept"#

#• " let y = 0, in equation, for x-intercept"#

#x=0to0+10y=30toy=3larrcolor(red)" y-intercept"#

#y=0to5x+0=30tox=6larrcolor(red)" x-intercept"#

#"plot the points " (0,3)" and " (6,0)# draw a straight line through them and you have the graph.
graph{-1/2x+3 [-10, 10, -5, 5]}