# How do you graph #-8x+10y=40# using intercepts?

##### 2 Answers

#### Answer:

see explanation.

#### Explanation:

To find the

#color(blue)" x and y intercepts"#

#• " let x = 0, in the equation, to find y-intercept"#

#• " let y = 0, in the equation, to find x-intercept"#

#x=0to10y=40rArry=4larrcolor(red)" y-intercept"#

#y=0to-8x=40rArrx=-5larrcolor(red)" x-intercept"# Plot the points (0 ,4), (-5 ,0) and draw a straight line through them for the graph.

graph{4/5x+4 [-11.25, 11.25, -5.625, 5.625]}

#### Answer:

Plug in

See below for the solution with graph.

#### Explanation:

Keep in mind that the

It's easier to remember this if you think about the intercepts on a graph

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

First, find the

#-8x + 10(0) = 40#

#color(white)"XXXX--"-8x = 40#

#color(white)"XXXXXX.." x = -5#

The

Next, find the

#-8(0) + 10y = 40#

#color(white)"XXXXX-"10y=40#

#color(white)"XXXXXX.."y=4#

The

Finally, to graph the line, just graph these two points, and connect them, as shown below.