Question

How do you graph and find the discontinuities of `f(x) = (x - 1) / (x^2 - x - 6)`?

Answer 1

This function is discontinuous at `x_1=-2` and `x_2=3`

Explanation:

Such function is discontinuous at the points, which are the zeros of denominator, but are not zeroes of the numerator.

In this case the numerator is zero for `x=1`, and the denominator is zero for `x_1=-2` and `x_2=3`

graph{(x-1)/(x^2-x-6) [-10, 10, -5, 5]}