# How do you graph and find the discontinuities of #R(x) = (x^2 + x - 12)/(x^2 - 4)#?

##### 1 Answer

Sep 5, 2015

The graph would appear to be as in the given figure.

#### Explanation:

The graph has two vertical asymptotes at x^2-4=0, that is at x=2 and x= -2

R(x) can also be written as R(x)= 1 +

At x=0, y=3

The graph would cross x axis at R(x)=0, that is when

The graph would appear like this