How do you graph and solve #2x-abs[x+4]> 8#?

1 Answer
Oct 27, 2017

Answer:

#x > 12#

Explanation:

#2x-abs(x+4)=8+epsilon^2# with #epsilon ne 0# or

#2x-8-epsilon^2= abs(x+4)# or

#(2x-8-epsilon^2)^2-(x+4)^2=0# or

#(-epsilon^2 - 12 + x) (-epsilon^2 - 4 + 3 x) = 0# or

#{(-epsilon^2 - 12 + x=0),(-epsilon^2 - 4 + 3 x=0):}#

or

#{(x > 12),(x > 4/3):}#

and the solution is #x > 12#