# How do you graph and write a linear equation with m=3/2 and point (1,0)?

Jun 3, 2018

Solve for the y intercept, put the y intercept in for b.
Start at b (0,b) for the first point go up 3 and over 2 for the second point and connect the points.

#### Explanation:

$y = m x + b$
$y = 0$
$x = 1$
$m = \frac{3}{2}$

$0 = \frac{3}{2} \times 1 + b$

$0 = \frac{3}{2} + b$ subtract - 3/2 from both sides

$0 - \frac{3}{2} = \frac{3}{2} - \frac{3}{2} + b$

$- \frac{3}{2} = b$

The first point is ( 0, -3/2)

$- \frac{3}{2} + 3 = - \frac{3}{2} + \frac{6}{2} = + \frac{3}{2}$
$0 + 2 = 2$

The second point is ( 2, + 3/2)

Plot the two points and connect them with a line.

The equation is

$y = \frac{3}{2} x + - \frac{3}{2}$