How do you graph #f(x) - 1/2x - 3# by plotting points?

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Answer 1 · 2017-10-07T14:09:17

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (1/2 xx 0) - 3#

#y = 0 - 3#

#y = -3# or #(0, -3)#

Second Point: For #x = 2#

#y = (1/2 xx 2) - 3#

#y = 1 - 3#

#y = -2# or #(2, -2)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.04)((x-2)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 1/2x + 3)(x^2+(y+3)^2-0.04)((x-2)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}