How do you graph #f(x)= 1+ cosx #?

1 Answer
Apr 23, 2018

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Please read the explanation.

Explanation:

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To graph #color(red)(f(x)=1+Cos(x)#,

start working on it's Parent Function #color(blue)(f(x) = Cos(x)# first.

Make a table of values for #f(x)=Cos(x) and f(x)=1+cos(x)#

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For #color(red)(x#, consider the values #color(red)(0, pi/2, pi, (3pi)/2 and 2pi#.

If you examine #color(green)("Col 4" and "Col 5"#, you see that the difference is 1.

#color(red)("Graph of y = f(x) = Cos(x)"#

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#color(red)("Graph of y = f(x) = 1 + Cos(x)"#

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#color(red)("Graph of y = f(x) = Cos(x)")# & #color(blue)("y = f(x) = 1 + Cos(x)"#

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Use #color(green)(y=A*sin(Bx+C)+D# [ or ]

use #color(green)(y=A*cos(Bx+C)+D#,

where, Amplitude is #|A|#

Period is #(2pi)/B# and

Vertical Shift is #D#

Since #D=1#, the graph is shifted vertically by 1 unit.

If #D# is given, the value of #D# is responsible for a vertical shift.

Hope it helps.