# How do you graph #f(x)=-1/(x-2)# using holes, vertical and horizontal asymptotes, x and y intercepts?

##### 1 Answer

Feb 15, 2017

There is a vertical asymptote at

#### Explanation:

Analytically:

Setting the numerator =

Setting the denominator =

Horizontal asymptotes are found based on the degree of the numerator and denominator. If the degree of the numerator is one less than the degree of the denominator, the horizontal asymptote is the x-axis (

Since there is no variable in the numerator, the degree = 0.

The degree of the denominator is 1.

From the graph:

graph{-1/(x-2) [-10, 10, -5, 5]}