Question

How do you graph `f(x)=3cos(1/3x-pi/6)`?

Answer 1

`y = f ( x ) = 3 cos ( 1/3 x - 1/6pi ) in [ -3, 3 ]`

The period for this cosine wave = `(2pi)/(1/3) = 6pi`

Amplitude = 3

Wave axis: y = 0
Phase shift `= (1/6pi)/(1/3) = pi/2`
See the graph, depicting all these aspects.
graph{(y-3cos(1/3x-1/6pi))(y-3+0y)(y+3+0y)(x-3pi +0y)(x+3pi+0y)=0[-20 20 -12 8]}