How do you graph #f(x)=(x+2)/(x^2+4)# using holes, vertical and horizontal asymptotes, x and y intercepts?

1 Answer
Dec 18, 2017

Answer:

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Explanation:

The horizontal asymptote is y= 0 because the denominator exponent is larger than the numerator.
There is an x intercept of -2 because the numerator is #(x+2)#
there are no vertical asymptotes because the denominator does not factor.
There are no holes, because no two terms cancel eachother out.
The Y intercept is #1/2#, because when you plug 0 in for x in the equation, you get #2/4# which is #1/2#.