Question

How do you graph `f(x)=x^2 - x+3` by plotting points?

Answer 1

See explanation

Explanation:

`color(brown)("As "x^2" is positive the graph is of form "uu)`

Additional comment: if we had `-x^2` then the graph would be `nn`

For a moment consider the equation as: `y=x^2color(red)(-1)xcolor(magenta)(+3)`

`color(green)("Then "x_("vertex") = (-1/2)xxcolor(red)(-1)=+1/2 ->(x,y)=(1/2,y))`

`color(green)("Also "y_("intercept") = color(magenta)(+3) ->(x,y)=(0,3))`

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Build a table of values.

Mark your points and draw a curved line `uu` through all the points as best as you can. To obtain mote marks show you table. Either on the graph itself or separately.

`color(red)("I have only shown a few of the points")`