How do you graph #h(x) = 2 sin(πx−3π) − 4#?

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Answer 1 · 2018-06-07T07:22:50

As below.

#h(x) = 2 sin (pi x - 3pi) - 4#

Standard form is #y = A sin (Bx - C) + D#

#A = 2, B = pi, C = 3pi, D = -4#

#Amplitude = |A| = 2#

#"Period " = (2pi) / |B| = (2pi) / pi = 2#

#"Phase Shift " = -C / B = (3pi) / pi = 3#, #color(red)(3 " to the right"#

#"Vertical Shift " = D = -4#

graph{2 sin (pi x - 3pi) - 4 [-10, 10, -5, 5]}