How do you graph #sqrtx", if "x>0 and -1/2x+3", if "x≤ 0#?
Any number that is negative times its self will give a positive answer.
Any number that is positive times itself will give a positive answer.
So in this case
This is a roundabout way of writing
So really this is a quadratic in
Firstly this is an equation of a straight line: form
The gradient (
The plot well terminate at the y-axis so there is no line on and to the right of the y-axis.
Pick any value for
Mark the point
Using a ruler line this up with the value of 3 on the x-axis and draw your line making sure you do not go beyond the y-axis into the zone