# How do you graph the circle #x^2+y^2+3x+4y+4=0#?

##### 1 Answer

Jan 25, 2016

#### Answer:

graph{(x-3/2)^2 + (y-2)^2 - 9/4 = 0 [-2.205, 5.55, -0.087, 3.954]}

#### Explanation:

Step 1. Group x and y terms together.

Now the goal to build a perfect by setting

Now the circle equation in standard form is:

And the circle equation in standard form is