How do you graph the equation by plotting points #3x-2y=15#?

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Answer 1 · 2017-10-27T13:34:16

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 1#

#(3 * 1) - 2y = 15#

#3 - 2y = 15#

#-3 + 3 - 2y = -3 + 15#

#0 - 2y = 12#

#-2y = 12#

#(-2y)/-2 = 12/-2#

#y = -6# or #(1, -6)#

Second Point: For #y = 0#

#3x - (2 * 0) = 15#

#3x - 0 = 15#

#3x = 15#

#(3x)/color(red)(3) = 15/color(red)(3)#

#x = 3# or #(5, 0)#

We can next plot the two points on the coordinate plane:

graph{((x-1)^2+(y+6)^2-0.075)((x-5)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x-2y-15)((x-1)^2+(y+6)^2-0.075)((x-5)^2+y^2-0.075)=0 [-20, 20, -10, 10]}