How do you graph the equation by plotting points #3x - 2y =4#?

1 Answer
May 7, 2016

Function: #y=-2+3/2x#
Intercepts: (#0, -2#) and (#4/3, 0#). The graph is a line that passes through these points.

Explanation:

First of all, you must make a function out of this equation. A function is defined as #y=f(x)#, so you can start by isolating #y#:

#-2y=4-3x#
#y=(4-3x)/-2 = -2+3/2x#

Next, since this is a linear function, you can find the intercepts of the function.
With #x=0#:
#y=-2+cancel(3/2*(0))=-2#

And with #y=0#:
#0=-2+3/2x#
#3x/2=2#
#3x=4#
#x=4/3#

We now have the points (#0, -2#) and (#4/3, 0#). We can just make a line that passes through them in the graph:

graph{3/2x-2 [-5, 5, -5, 5]}