How do you graph the equation by plotting points #-x + 3y = -9#?

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Answer 1 · 2016-01-13T03:46:39

Refer the explanation section

Given -

#-x+3y=-9#

It is in the form >
#ax+by=c#

Then -

Y- intercept is #y=c/b=(-9)/3=-3#

One of the points is #(0, -3)#

X-Intercept is #x=c/a=(-9)/(-1)=9#

Another point is #(9, 0)#

Plot these two points and join them with the help of a straight line.

Refer the picture