How do you graph the function and its inverse of $f(x)=absx+1$ ?

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Answer 1 · 2016-12-22T14:46:49

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The graph of $f(x) = abs(x)+1$ is a 'V' shape with slope $+-1$ and vertex at $(0, 1)$ :

graph{abs(x)+1 [-10, 10, -5, 5]}

The graph of the inverse relation (it is not a function) is formed by reflecting the above graph in the $y=x$ line:

graph{x=abs(y)+1 [-10, 10, -5, 5]}

For any $x > 1$ this relation has two possible $y$ values, so fails the vertical line test and is not a function.

How do you graph the function and its inverse of f(x)=absx+1f(x)=absx+1?