How do you graph the function #f(x) = –x^3 + 2#?

1 Answer
Sep 3, 2015

Refer Explanation Section.

Explanation:

Given -

y = #-x^3 +2

This is a cubic function.
It will pass through (0, 2)
At x = 0: y =# - 0^2 + 2# = 2

Take a few x values on either side of x = 0 .
Calculate corresponding y values.

Plot the pairs.
Join them with the help of a smooth curve.

x: y
-3: 29
-2: 10
-1 :3
0 :2
1 :1
2 :-6
3 : graph{-x^3+2 [-10, 10, -5, 5]} -25