How do you graph the function #r^2 = 9cos(2θ)#?
1 Answer
Nov 17, 2016
I have inserted the graph of this Lemniscate, using the Socratic facility for the cartesian frame.
Explanation:
The period of
period can be chosen as
wherein
As
initial line.
Also, as cos (2(pi-theta) = cos 2theta, the graph is symmetrical
about the vertical
A Table for half period
Use symmetry. for the other three quarters..
graph{(x^2+y^2)^2=9(x^2-y^2) [-10, 10, -5, 5]}